问题 解答题

计算.

(1)(a-2)2+4(a-1)

(2)(a+2)(a+2)-a(a+1)

(3)(a-b-1)(a+b-1)

(4)(x+2y)2(x-2y)

答案

(1)原式=a2-4a+4+4a-4

=a2

(2)原式=a2-4-a2-a

=-a-4;

(3)原式=(a-1)2-b2

=a2-2a+1-b2

(4)原式=(x2+4xy+4y2)(x-2y)

=x3-4xy2+2x2y-8y3

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