问题
解答题
先化简,再求值:[(x2+y2)-(x-y)2+2y(x-y)]÷4y,其中x=3,y=-4.
答案
[(x2+y2)-(x-y)2+2y(x-y)]÷4y,
=(4xy-2y2)÷4y,
=x-
y;1 2
当x=3,y=-4时,原式=3-
×(-4)=5.1 2
先化简,再求值:[(x2+y2)-(x-y)2+2y(x-y)]÷4y,其中x=3,y=-4.
[(x2+y2)-(x-y)2+2y(x-y)]÷4y,
=(4xy-2y2)÷4y,
=x-
y;1 2
当x=3,y=-4时,原式=3-
×(-4)=5.1 2