问题 填空题
如果x+
1
x
=2,则
x2
x4+x2+1
=______.
答案

∵(x+

1
x
2=x2+2+
1
x2
=4,

∴x2+

1
x2
=2,

x2
x4+x2+1
=
1
x2+1+
1
x2
=
1
3

故本题答案为:

1
3

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