问题 解答题

计算:

(1)(x-6)2

(2)(-2x-y)2

(3)(-p+3q)2

(4)[(2m+n)(2m-n)]2

答案

(1)原式=x2-2•x•6+62

=x2-12x+36;

(2)原式=(-2x)2+2•(-2x)•(-y)+(-y)2

=4x2+4xy+y2

(3)原式=(-p)2+2•(-p)•3q+(3q)2

=p2-6pq+9q2

(4)原式=[4m2-n2]2

=16m4-8m2n2+n4

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