问题
解答题
分解因式:
(1)2x2-x;
(2)16x2-1;
(3)6xy2-9x2y-y3;
(4)4+12(x-y)+9(x-y)2.
答案
(1)2x2-x=x(2x-1);
(2)16x2-1=(4x+1)(4x-1);
(3)6xy2-9x2y-y3,
=-y(9x2-6xy+y2),
=-y(3x-y)2;
(4)4+12(x-y)+9(x-y)2,
=[2+3(x-y)]2,
=(3x-3y+2)2.