问题 解答题

分解因式:

(1)2x2-x;

(2)16x2-1;

(3)6xy2-9x2y-y3

(4)4+12(x-y)+9(x-y)2

答案

(1)2x2-x=x(2x-1);

(2)16x2-1=(4x+1)(4x-1);

(3)6xy2-9x2y-y3

=-y(9x2-6xy+y2),

=-y(3x-y)2

(4)4+12(x-y)+9(x-y)2

=[2+3(x-y)]2

=(3x-3y+2)2

解答题
单项选择题 A1/A2型题