把下列各式分解因式: (1)x3y-xy3; (2)(x2+1)2-4x2; (3)先化简再求值,
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(1)原式=xy(x2-y2)
=xy(x+y)(x-y);
(2)原式=(x2+1-2x)(x2+1+2x)
=(x-1)2(x+1)2;
(3)原式=
÷x-y x (x-y)2 x
=
×x-y x x (x-y)2
=
,1 x-y
当x=2009,y=2010时,原式=
=-1.1 2009-2010
把下列各式分解因式: (1)x3y-xy3; (2)(x2+1)2-4x2; (3)先化简再求值,
|
(1)原式=xy(x2-y2)
=xy(x+y)(x-y);
(2)原式=(x2+1-2x)(x2+1+2x)
=(x-1)2(x+1)2;
(3)原式=
÷x-y x (x-y)2 x
=
×x-y x x (x-y)2
=
,1 x-y
当x=2009,y=2010时,原式=
=-1.1 2009-2010