问题
填空题
在实数范围内分解因式:3x2-6x+1=______.
答案
3x2-6x+1
=3(x2-2x+
)1 3
=3[(x-1)2-
]2 3
=3(x-1+
)(x-1-6 3
)6 3
=3(x-
)(x-3+ 6 3
).3- 6 3
故答案为3(x-
)(x-3+ 6 3
).3- 6 3
在实数范围内分解因式:3x2-6x+1=______.
3x2-6x+1
=3(x2-2x+
)1 3
=3[(x-1)2-
]2 3
=3(x-1+
)(x-1-6 3
)6 3
=3(x-
)(x-3+ 6 3
).3- 6 3
故答案为3(x-
)(x-3+ 6 3
).3- 6 3