问题
解答题
分解因式:
(1)x3y-xy3;
(2)(a+1)(a2+2a-1)+2(a+1).
答案
(1)x3y-xy3
=xy(x2-y2)
=xy(x+y)(x-y);
(2)(a+1)(a2+2a-1)+2(a+1)
=(a+1)(a2+2a+1)
=(a+1)3.
分解因式:
(1)x3y-xy3;
(2)(a+1)(a2+2a-1)+2(a+1).
(1)x3y-xy3
=xy(x2-y2)
=xy(x+y)(x-y);
(2)(a+1)(a2+2a-1)+2(a+1)
=(a+1)(a2+2a+1)
=(a+1)3.