问题
填空题
分解因式:x4-5x2+4x=______.
答案
x4-5x2+4x
=x(x3-x-4x+4)
=x[x(x2-1)-4(x-1)]
=x[x(x-1)(x+1)-4(x-1)]
=x(x-1)(x2+x-4)
=x(x-1)(x-
)(x--1+ 17 2
).-1- 17 2
故答案为:x(x-1)(x-
)(x--1+ 17 2
).-1- 17 2
分解因式:x4-5x2+4x=______.
x4-5x2+4x
=x(x3-x-4x+4)
=x[x(x2-1)-4(x-1)]
=x[x(x-1)(x+1)-4(x-1)]
=x(x-1)(x2+x-4)
=x(x-1)(x-
)(x--1+ 17 2
).-1- 17 2
故答案为:x(x-1)(x-
)(x--1+ 17 2
).-1- 17 2