问题
解答题
计算:(
|
答案
设:m=
+1 2
+…1 3
,则1 1998
原式=(m+
)(1+m)-(1+m+1 1999
)m1 1999
=(m+㎡+
+1 1999
)-(m+㎡+m 1999
),m 1999
=1 1999
计算:(
|
设:m=
+1 2
+…1 3
,则1 1998
原式=(m+
)(1+m)-(1+m+1 1999
)m1 1999
=(m+㎡+
+1 1999
)-(m+㎡+m 1999
),m 1999
=1 1999