问题
解答题
计算: (1)(-8)-(-2) (2)25×
(3)-22÷
(4) 3a-[5a-(2a-1)] |
答案
(1)原式=-8+2=-6;
(2)原式=25×(
-3 4
-1 2
)=25×0=0;1 4
(3)原式=-4÷
-4 3
×12+1 4
×12=-3-3+10=4;5 6
(4)原式=3a-3a-1=-1.
计算: (1)(-8)-(-2) (2)25×
(3)-22÷
(4) 3a-[5a-(2a-1)] |
(1)原式=-8+2=-6;
(2)原式=25×(
-3 4
-1 2
)=25×0=0;1 4
(3)原式=-4÷
-4 3
×12+1 4
×12=-3-3+10=4;5 6
(4)原式=3a-3a-1=-1.