将基因型为AaBbCc和AABbCc的向日葵杂交,按基因自由组合规律,后代中基因型为AABBCC的个体比例应为 [ ]
A.1/8
B.1/6
C.1/32
D.1/64
答案:C
下列各组物质相互作用,生成物不随反应条件或反应物用量的变化而变化的是[ ]
A.Na和O2
B.NaOH和CO2
C.NaHCO3和NaOH
D.Na2CO3和HCl
I wish you success in your career.()
A.You are welcome.
B.I think so
C.Yes, please.
D.The same to you.