问题
解答题
耐心算一算 (1)
(2)3.5÷(-
(3)(
(4)(-3)2×(-2)-[(-2)×(-1)]2 (5)(4x2y-3xy2)-(1+4x2y-3xy2) (6)4y2-[3y-(3-2y)+2y2]. |
答案
(1)原式=(
+2 3
)+(-1 3
-1 8
)=1-3 8
=1 2
;1 2
(2)原式=
×(-7 2
)×(-8 7
)=3;3 4
(3)原式=-3-2+6=1;
(4)原式=9×(-2)-4=-18-4=-22;
(5)原式=4x2y-3xy2-1-4x2y+3xy2=-1;
(6)原式=4y2-3y+3-2y-2y2=2y2-5y+3.