直线y=-3x+b经过点A(0,2),则b的值是b=______.
点A(0,2)代入直线y=-3x+b
得:b=2.
故填2.
计算下列各题:
(1)(a-1)(a+1)=__________
(a-1)(a2+a+1)=__________
(a-1)(a3+a2+a+1)=_________
……
根据前面各式的规律,请你写出:
(a-1)(an+an-1+an-2+…+a3+a2+a+1)=__________;
(2)利用(1)的结论,计算:
299+298+297+…+22+2+1
限制型心肌病(restrictive cardiomyopathy,RCM)