问题
解答题
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答案
0.1×0.1=0.01, | 0.24×0.5=0.12, | 5.4+3.6=9, | 1.25-0.25=1, | 6.45×0.01=0.0645. |
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0.1×0.1=0.01, | 0.24×0.5=0.12, | 5.4+3.6=9, | 1.25-0.25=1, | 6.45×0.01=0.0645. |
系A到系J是顺反子y的一系列缺失,它们的表现程度用下图中实线表示。今将突变系1到10同系A到系J的每个系杂交,得到下面结果(“+”和“0”表示后代中野生型的出现与否)。指出顺反子y中从左到右的突变系1到10的顺序。
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | |
A | 0 | 0 | 0 | 0 | 0 | + | 0 | 0 | + | 0 |
B | + | 0 | 0 | + | + | + | 0 | 0 | + | 0 |
C | + | 0 | 0 | + | + | + | 0 | + | + | 0 |
D | + | + | 0 | + | + | + | 0 | + | + | 0 |
E | 0 | 0 | + | 0 | + | + | + | 0 | + | 0 |
F | + | + | 0 | + | + | + | + | + | + | 0 |
G | 0 | + | + | + | 0 | 0 | + | + | 0 | + |
H | 0 | + | + | 0 | 0 | 0 | + | 0 | 0 | 0 |
I | + | + | + | + | 0 | 0 | + | + | 0 | + |
J | + | + | + | + | + | + | + | + | 0 | + |