若实数a、b、c、d满足a2+b2+c2+d2=10,则y=(a-b)2+(a-c)2+(a-d)2+(b-c)2+(b-d)2+(c-d)2的最大值是______.
∵a2+b2+c2+d2=10,
∴y=(a-b)2+(a-c)2+(a-d)2+(b-c)2+(b-d)2+(c-d)2,
=a2+b2-2ab+a2+c2-2ac+b2+c2-2bc+b2+d2-2bd+c2+d2-2cd,
=3(a2+b2+c2+d2)-2ab-2ac-2ad-2bc-2bd-2cd,
=4(a2+b2+c2+d2)-(a+b+c+d)2,
=40-(a+b+c+d)2,
∵(a+b+c+d)2≥0,
∴当(a+b+c+d)2=0时,y的最大值为40.
故答案为:40.