问题 解答题
化简或求值:
(1)化简:(2m-3n+7)-(-6m+5n+2)
(2)已知|x+2|+(y-
1
2
)2
=0,求4xy-[(x2+5xy-y2)-(x2+3xy)]的值.
答案

(1)原式=2m-3n+7+6m-5n-2=8m-8n+5;

(2)原式=4xy-x2-5xy+y2+x2+3xy=2xy+y2

∵|x+2|+(y-

1
2
2=0,∴x+2=0,y-
1
2
=0,

解得:x=-2,y=

1
2

则原式=-2+

1
4
=-1
3
4

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