问题 选择题

已知平面简谐横波在x轴上传播,原点O的振动图线如图12-2-13甲所示,某时刻的波形图线如图12-2-14乙所示.

图12-2-13

在t′="t+0.5" s时刻的波形图可能是图12-2-14中的(   )

图12-2-14

答案

CD

由甲可知O简谐横波的周期T="0.4" s,则t′=t+,可见,在t′时刻的波形相对于图乙有两种可能:①如波沿x轴正方向传播,则应为D图;②如波沿x轴负方向传播,则应为C图.

阅读理解

阅读短文,选择正确答案。

      "Who has more questions, a teacher or a student?" About this question a great learned man told his student

that nobody does but a teacher.

      The student got puzzled. With a smile, the teacher drew two circles (圆). Within (在……里面) the larger

one is my knowledge of things, and within the smaller one is yours. Out of the circles is still unknown to both

of us. Since mine is larger, as you can see, the line that marks out the circle is longer. That makes it clear that

who has more chances (机会) to face something still unknown.

1. The great learned man believed that ________. [ ]

A. a teacher has more questions

B. a student has more questions

C. both a teacher and a student have questions

D. everyone, except a teacher, has more questions

2. The student thought that ________. [ ]

A. a student's knowledge is less than his teacher's because it comes from the teacher

B. a teacher can not necessarily answer all the questions his students ask

C. those who have less knowledge have more questions

D. anyone who learns more has more questions

3. At the end of the story, the great learned man concluded (推断) that ________. [ ]

A. a student should learn from his teacher

B. a teacher does not have so many questions as his student

C. a student knows more than his teacher

D. a teacher has more chances to face what he doesn't know

4. Which of the following topics can NOT express the idea of the story? [ ]

A. You Will Never Learn Enough.

B. A Teacher and His Student.

C. There Is No Limit to Knowledge.

D. One Is Never Too Old to Learn.

5. We can often find such an article in ________. [ ]

A. the Palace Museum

B. any book

C. a newspaper of magazine

D. An encyclopedia (百科全书)

问答题

短周期元素A、B、C、D原子序数依次增大,且C元素最高价氧化物对应的水化物,能电离出电子数相等的阴、阳离子.A、C位于同一主族,A为非金属元素,B的最外层电子数是次外层的3倍,B、C的最外层电子数之和与D的最外层电子数相等.E单质是生活中常见金属,其制品在潮湿空气中易被腐蚀或损坏.

请回答下列问题:

(1)C的最高价氧化物对应水化物电子式为______,其中含有的化学键类型为______.

(2)由上述A、B、C、D四种元素中的三种组成某种盐,水溶液显碱性,是家用消毒剂的主要成分.将该盐溶液滴入KI淀粉溶液中,溶液变为蓝色,则反应的离子方程式为______

(3)用石墨电极电解CD的饱和溶液,若反应后溶液的体积为200mL,测得pH为13,则阳极得到的气体的物质的量为______mol.

(4)E元素与D元素可形成ED2和ED3两种化合物,下列说法正确的是(填序号)______.

①保存ED2溶液时,需向溶液中加入少量E单质

②ED2只能通过置换反应生成,ED3只能通过化合反应生成

③铜片、碳棒和ED3溶液组成原电池,电子由铜片沿导线流向碳棒④向淀粉碘化钾溶液和苯酚溶液中分别滴加几滴ED3的浓溶液,原无色溶液都变成紫色

(5)25℃时,将pH=4.00的A元素与D元素形成化合物AD的水溶液稀释1.00×103倍,则稀释后溶液中各离子浓度必遵循的定量等式关系式是______.

(6)将一定量的D单质通入一定浓度的苛性钾溶液,两者恰好完全反应(已知反应过程放热),生成物中有三种含D元素的离子,其中两种离子的物质的量(n)与反应时间(t)的变化示意图如图所示.该苛性钾溶液中KOH的质量是______.