问题
解答题
解下列方程:
(1)x2-2x-3=0;
(2)(x-1)(x+2)=4
答案
(1)x2-2x-3=0,
(x-3)(x+1)=0,
x1=3,x2=-1.
(2)(x-1)(x+2)=4,
x2+x-2=4,
x2+x-6=0,
(x-2)(x+3)=0,
x1=2,x2=-3.
解下列方程:
(1)x2-2x-3=0;
(2)(x-1)(x+2)=4
(1)x2-2x-3=0,
(x-3)(x+1)=0,
x1=3,x2=-1.
(2)(x-1)(x+2)=4,
x2+x-2=4,
x2+x-6=0,
(x-2)(x+3)=0,
x1=2,x2=-3.