问题
填空题
已知tan(α+
|
答案
tan(α+β)=tan[(α+
)+(β-π 6
)]=π 6 tan(α+
)+tan(β-π 6
) π 6 1-tan(α+
) tan(β-π 6
)π 6
=
=1
+1 2 1 3 1-
×1 2 1 3
故答案为:1
已知tan(α+
|
tan(α+β)=tan[(α+
)+(β-π 6
)]=π 6 tan(α+
)+tan(β-π 6
) π 6 1-tan(α+
) tan(β-π 6
)π 6
=
=1
+1 2 1 3 1-
×1 2 1 3
故答案为:1