问题
解答题
解方程: (1)2x2-3x-3=0;(用配方法) (2)x2-(
|
答案
(1)2x2-3x-3=0
x2-
x-3 2
=03 2
(x-
)2=3 4 33 16
x-
=±3 4 33 4
x1=
,x2=3+ 33 4
;3- 33 4
(2)x2-(
+1)x+2
=02
(x-1)(x-
)=02
x1=1,x2=
.2
解方程: (1)2x2-3x-3=0;(用配方法) (2)x2-(
|
(1)2x2-3x-3=0
x2-
x-3 2
=03 2
(x-
)2=3 4 33 16
x-
=±3 4 33 4
x1=
,x2=3+ 33 4
;3- 33 4
(2)x2-(
+1)x+2
=02
(x-1)(x-
)=02
x1=1,x2=
.2