问题 选择题

某一单摆的位移-时间如图所示,则该单摆的(        )

A.振幅是0.20m

B.周期为1.25S

C.频率为1.0Hz

D.摆长为1.0m

答案

答案:C

题目分析:由图读出单摆的周期,由周期公式得,摆长,代入解得.故BD错误.频率.故C正确.振幅等于位移的最大值,由图读出振幅A=0.1m.故A错误.故选C

点评:由振动图象读出振幅、周期及某一时刻的位移、速度方向、加速度方向及速度和加速度大小的变化情况,是应培养的基本能力.

阅读理解

阅读短文,回答问题。

                                                         Mrs Fang’s Day

     At 7: 40 when Mrs Fang is at breakfast, there comes a call. Twenty minutes later, she is with Ann,

because she cannot stop her baby from crying. There, Mrs Fang helps wash Ann’s three-day-old

baby and it calms (安静)down. It is her first child and she is learning what to do. After that, Mrs

Fang goes on to see Mr Johnson, a rich old man who lives alone. His arm was broken and cannot

wash or put on his clothes himself. He must be looked after every day.

     Then Mrs Fang gets her second call that day. She goes to the home for the old. There she works

with the old people till 2: 00 p. m. One by one, she answers their questions and helps them take

their medicine, while the doctor takes care of other more serious problems.

     Mrs Fang keeps hurrying around all day and sometimes she can be rung up even late at night

when the sick must be helped. She is busy, but she likes her job and enjoys helping others. 

1. Who does Mrs Fang get her first call from?

    _________________________________________

2. What does Mrs Fang help Ann do?          

    _________________________________________

3. Why does Mrs Fang look after Mr Johnson?  

    _________________________________________

4. What does Mrs Fang do for the old people?  

    _________________________________________

5. Why does Mrs Fang like her job?            

    _________________________________________                                              

问答题 论述题