搜题请搜索小程序“爱下问搜题”
问题 单项选择题

垂体性发现一6.8mm×7.5mm大小腺瘤

A．经蝶窦切除垂体微腺瘤
B．垂体放疗
C．一侧肾上腺肿瘤摘除
D．开颅手术+垂体放疗
E．一侧肾上腺全切+另侧肾上腺大部切除，术后作垂体放疗

答案

参考答案：A

单项选择题

糖尿病患者，70岁，昏迷1天入院，血压80/50mmHg，血糖18mmol/L，血钠155mmol/L，尿糖++++，酮体+++，首选治疗措施是()

A.小剂量胰岛素及等渗盐水静脉滴注 

B.小剂量胰岛素及低渗盐水静脉滴注 

C.大剂量胰岛素及等渗盐水静脉滴注 

D.输入胶体溶液 

E.快速补碱 
查看答案
问答题

试题一 阅读下列说明，回答问题。 【说明】 逻辑覆盖法是设计白盒测试用例的主要方法之一，通过对程序逻辑结构的遍历实现程序的覆盖。针对以下由C语言编写的程序，按要求回答问题。 int XOR(char * filename, unsigned long key){ FILE * input = NULL , *output = NULL; //i char * outfilename = NULL; int len = strlen(filename); unsigned char buffer; if( (filename[len-2] == ’.’) && (filename[len-1] == ’c’) ) { //2,3 outfilename = new char[len+1]; //4 strcpy(outfilename, filename); outfilename[len-2] = ’\0’; } else{ //5 outfilename = new char[len+5]; strcpy(outfilename, filename); strncat(outfilename,".c",2); } input = fopen(filename,"rb"); if( input == NULL) { //6 cout ＜＜ "Error opening file " ＜＜ filename ＜＜ endl; //7 delete [] outfilename; outfilename = NULL; return 1; } output = fopen(outfilename,"wb"); if( output == NULL ) { //8 cout ＜＜ "Error creating output file " ＜＜ outfilename ＜＜ endl; //9 delete [] outfilename; outfilename = NULL; return 1; } while( ! feof(input) ) { //10 if( fread(&buffer,sizeof(unsigned char),1,input) != 1 ) { //11 if( ! feof(input) ) { //12 delete [] outfilename; //13 outfilename = NULL; fclose(input); fclose(output); return 1; } } else{ //14 buffer ^= key; fwrite(&buffer, sizeof(unsigned char),1,output); } } fclose(input); //15 fclose(output); delete [] outfilename; return 0; }

请给出满足100%DC（判定覆盖）所需的逻辑条件。
查看答案