问题
解答题
已知sinα=
(1)求tanα的值; (2)求tan(α+2β)的值. |
答案
(1)∵sinα=
,α∈(0,5 5
),π 2
∴cosα=
=1-sin2α
=1- 1 5
.2 5 5
∴tanα=
=sinα cosα
=5 5 2 5 5
.1 2
(2)∵tanβ=
,1 3
∴tan2β=
=2tanβ 1-tan2β
=2× 1 3 1-(
)21 3
.3 4
∴tan(α+2β)=
=tanα+tan2β 1-tanαtan2β
=2.
+1 2 3 4 1-
×1 2 3 4