问题 填空题
(文)对于任意的平面向量
a
=(x1y1),
b
=(x2y2)
,定义新运算⊕:
a
b
=(x1+x2y1y2)
.若
a
b
c
为平面向量,k∈R,则下列运算性质一定成立的所有序号是______.
a
b
=
b
a
;            
(k
a
)⊕
b
=
a
⊕(k
b
)

a
⊕(
b
c
)=(
a
b
)⊕
c
;   
a
⊕(
b
+
c
)=
a
b
+
a
c
答案

a
b
=(x1+x2,y1y2)=(x2+x1y2y1)=
b
a
,故正确;

②∵(k

a
)⊕
b
=(kx1+x2,ky1y2),
a
(k
b
)
=(x1+kx2,y1ky2),

(k

a
)⊕
b
a
(k
b
)
,故不正确;

③设

c
=(x3y3),

a
(
b
c
)
=
a
⊕(x2+x3,y2y3)=(x1+x2+x3,y1y2y3),

a
b
)⊕
c
=(x1+x2,y1y2)⊕
c
=(x1+x2+x3,y1y2y3),

a
⊕(
b
c
)=(
a
b
)⊕
c
,故正确;

④设

c
=(x3y3),

a
(
b
c
)
=
a
⊕(x2+x3,y2y3)=(x1+x2+x3,y1y2y3),

a
b
+
a
c
=(x1+x2,y1y2)+(x1+x3,y1y3)=(2x1+x2+x3,y1(y2+y3)),

a
⊕(
b
c
)≠
a
b
+
a
c
,故不正确.

综上可知:只有①③正确.

故答案为①③.

单项选择题
填空题