问题
填空题
已知点A(0,-2),B(0,4),动点P(x,y)满足
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答案
∵点A(0,-2),B(0,4),动点P(x,y)满足
•PA
=y2-8,PB
则有(x,y+2)•(x,y-4)=y2-8,即 x2+y2-2y-8=y2-8,
化简可得x2=2y,
故答案为x2=2y.
已知点A(0,-2),B(0,4),动点P(x,y)满足
|
∵点A(0,-2),B(0,4),动点P(x,y)满足
•PA
=y2-8,PB
则有(x,y+2)•(x,y-4)=y2-8,即 x2+y2-2y-8=y2-8,
化简可得x2=2y,
故答案为x2=2y.