问题
解答题
(1)计算:(
(2)解方程:x2-2x-3=0. |
答案
(1)原式=2-2
+3+6
×32 3 3 2
=5-2
+26 6
=5
(2)移项,得:x2-2x=3
配方x2-2x+12=3+12
(x-1)2=4
则x-1=±2
解得:x1=3,x2=-1
(1)计算:(
(2)解方程:x2-2x-3=0. |
(1)原式=2-2
+3+6
×32 3 3 2
=5-2
+26 6
=5
(2)移项,得:x2-2x=3
配方x2-2x+12=3+12
(x-1)2=4
则x-1=±2
解得:x1=3,x2=-1