问题
解答题
计算: (1)(2
(2)(4
|
答案
(1)原式=(
+215
)(3
-215
)=(3
)2-(215
)2=15-12=3;3
(2)原式=(4
)2-2×43
×23
+(26
)2=48-486
+24=72-482
.2
计算: (1)(2
(2)(4
|
(1)原式=(
+215
)(3
-215
)=(3
)2-(215
)2=15-12=3;3
(2)原式=(4
)2-2×43
×23
+(26
)2=48-486
+24=72-482
.2