问题
解答题
计算题和解方程 (1)(3
(2)(2x+1)2=3(2x+1) |
答案
(1)原式=(3
)2-12-[(2
)2-43
+22]3
=18-1-3+4
-43
=10+4
;3
(2)移项得:(2x+1)2-3(2x+1)=0,
(2x+1)(2x+1-3)=0,
2x+1=0,2x+1-3=0,
解得:x1=-
,x2=1.1 2
计算题和解方程 (1)(3
(2)(2x+1)2=3(2x+1) |
(1)原式=(3
)2-12-[(2
)2-43
+22]3
=18-1-3+4
-43
=10+4
;3
(2)移项得:(2x+1)2-3(2x+1)=0,
(2x+1)(2x+1-3)=0,
2x+1=0,2x+1-3=0,
解得:x1=-
,x2=1.1 2
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