问题
填空题
已知sinα-3cosα=0,则
|
答案
∵sinα-3cosα=0,即tanα=3,
∴
=sin2α cos2α-sin2α
=tan2α=sin2α cos2α
=2tanα 1-tan2α
=-2×3 1-32
.3 4
故答案为:-3 4
已知sinα-3cosα=0,则
|
∵sinα-3cosα=0,即tanα=3,
∴
=sin2α cos2α-sin2α
=tan2α=sin2α cos2α
=2tanα 1-tan2α
=-2×3 1-32
.3 4
故答案为:-3 4
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