问题 解答题
用递递等式计算.
4
5
-
4
5
÷4 
105×13-270÷18  
1
3
÷[(
2
3
+
1
5
)×
1
13
].
答案

(1)4÷

4
5
-
4
5
÷4,

=4×

5
4
-
4
5
×
1
4

=5-

1
5

=

24
5

(2)105×13-270÷18  

=1365-15,

=1350;

(3)

1
3
÷[(
2
3
+
1
5
)×
1
13
],

=

1
3
÷[(
10
15
+
3
15
)×
1
13
],

=

1
3
÷[
13
15
×
1
13
],

=

1
3
÷
1
15

=

1
3
×15,

=5.

单项选择题
单项选择题