问题
解答题
已知sinθ=
|
答案
∵sinθ=
且θ∈(4 5
,π),∴cosθ=-π 2
=-1-sin2θ
.3 5
∵cosϕ=-
且ϕ∈(5 13
,π),∴sinϕ=π 2
=1-cos2ϕ
.12 13
则sin(θ-ϕ)=sinθcosϕ-cosθsinϕ
=
×(-4 5
)-(-5 13
)×3 5
=12 13
.16 65
已知sinθ=
|
∵sinθ=
且θ∈(4 5
,π),∴cosθ=-π 2
=-1-sin2θ
.3 5
∵cosϕ=-
且ϕ∈(5 13
,π),∴sinϕ=π 2
=1-cos2ϕ
.12 13
则sin(θ-ϕ)=sinθcosϕ-cosθsinϕ
=
×(-4 5
)-(-5 13
)×3 5
=12 13
.16 65