问题
解答题
设向量
|
答案
∵向量
=(3,5,-4),a
=(2,1,8),∴3b
-2a
=3(3,5,-4)-2(2,1,8)=(9,15,-12)-(4,2,16)=(5,13,20);b
•a
=3×2+5×1+(-4)×8=-21;b
∵λ
+μa
=(3λ,5λ,-4λ)+(2μ,μ,8μ)=(3λ+2μ,5λ+μ,-4λ+8μ),且λb
+μa
与z轴垂直,b
∴(λ
+μa
)•(0,0,1)=0,b
∴-4λ+8μ=1.