问题
选择题
M={x|x2+x-6≤0},N={x||2x+1|>3},则M∩N=( )
A.(-3,-2]∪[1,2]
B.[-3,-2)∪(1,2]
C.(-3,-2)∪(1,+∞)
D.(-∞,-3)∪(1,2]
答案
∵M={x|x2+x-6≤0}={x|-3≤x≤2},N={x||2x+1|>3}═{x|x>1或x<-2},
∴M∩N=[-3,-2)∪(1,2]
故选B
M={x|x2+x-6≤0},N={x||2x+1|>3},则M∩N=( )
A.(-3,-2]∪[1,2]
B.[-3,-2)∪(1,2]
C.(-3,-2)∪(1,+∞)
D.(-∞,-3)∪(1,2]
∵M={x|x2+x-6≤0}={x|-3≤x≤2},N={x||2x+1|>3}═{x|x>1或x<-2},
∴M∩N=[-3,-2)∪(1,2]
故选B