问题
解答题
已知:
|
答案
由
=a,x y+z
=b,y z+x
=c代入z x+y
+a 1+a
+b 1+b
得:c 1+c
=
+x y+z 1+ x y+z
+y z+x 1+ y z+x
,z x+y 1+ z x+y
=
+x x+y+z
+y x+y+z
,z x+y+z
=
,x+y+z x+y+z
=1.
故答案为:1.
已知:
|
由
=a,x y+z
=b,y z+x
=c代入z x+y
+a 1+a
+b 1+b
得:c 1+c
=
+x y+z 1+ x y+z
+y z+x 1+ y z+x
,z x+y 1+ z x+y
=
+x x+y+z
+y x+y+z
,z x+y+z
=
,x+y+z x+y+z
=1.
故答案为:1.