问题
解答题
先化简,再求值:(
|
答案
(
-1)÷1 x-1 x2+2x+1 x2-1
=
•1-x+1 x-1 (x+1)(x-1) (x+1)2
=
.-x+2 x+1
当x=
-1时,2
原式=
=-
+1+22
-1+12
=3- 2 2
.3
-22 2
先化简,再求值:(
|
(
-1)÷1 x-1 x2+2x+1 x2-1
=
•1-x+1 x-1 (x+1)(x-1) (x+1)2
=
.-x+2 x+1
当x=
-1时,2
原式=
=-
+1+22
-1+12
=3- 2 2
.3
-22 2