问题 选择题 用换元法解方程x2-1x-xx2-1+2=0,如果设y=x2-1x,那么原方程可化为( )A.y2-y+2=0B.y2+y-2=0C.y2-2y+1=0D.y2+2y-1=0 答案 设y=x2-1x,则方程x2-1x-xx2-1+2=0变为y-1y+2=0,整理得y2+2y-1=0,故选D.