问题
解答题
计算: (1)-12+15-|-7-8| (2)(-3)×(-9)-(-5) (3)(-
(4)1÷(-3)×(-
(5)(-3)2-(-1
(6)-22×{[4
(7)(x2+2xy+y2)-(x2-xy+y2) (8)9a2-[7a2-2a-2(a2-3a)]-3 |
答案
(1-)-12+15-|-7-8|=-12+15-15=-12
(2)(-3)×(-9)-(-5)=27+5=32
(3)(-
+5 6
-2 3
)÷3 4
=(-1 12
+5 6
-2 3
)×12=-10+8-9=-113 4
(4)1÷(-3)×(-
)=1×1 3
×1 3
=1 3 1 9
(5)(-3)2-(-1
)3×1 2
-6÷(-2 9
)2=9-(-2 3
)×27 8
-6×2 9
=9+9 4
-3 4
=-27 2 15 4
(6)-22×{[4
÷(-4)+(-0•4)]÷(-2 3
)}=-4×{[1 3
×(-14 3
)-1 4
]×(-3)}=-4×[(-2 5
-7 6
)×(-3)]=-4×4.7=-18.82 5
(7)(x2+2xy+y2)-(x2-xy+y2)=x2+2xy+y2-x2+xy-y2=3xy
(8)9a2-[7a2-2a-2(a2-3a)]-3=9a2-7a2+2a+2a2-6a-3=4a2-4a-3