问题
解答题
去括号合并同类项:
(1)-5x+(3x-1)-2(3-x)
(2)2a2-[3a-(5a-2)+2a2].
答案
(1)原式=-5x+3x-1-6+2x=-7;
(2)原式=2a2-3a+5a-2-2a2=2a-2.
去括号合并同类项:
(1)-5x+(3x-1)-2(3-x)
(2)2a2-[3a-(5a-2)+2a2].
(1)原式=-5x+3x-1-6+2x=-7;
(2)原式=2a2-3a+5a-2-2a2=2a-2.