问题 解答题
(1)化简:
1
x+1
-
2x+1
1-x2

(2)先化简:
x2-1
x2-2x+1
+
x2-2x
x-2
÷x
,再在x=0,1,2,3中取一个你喜欢的x值代入求值.
答案

(1)原式=

1
x+1
+
2x+1
(x+1)(x-1)

=

x-1
(x+1)(x-1)
+
2x+1
(x+1)(x-1)

=

x-1+2x+1
(x+1)(x-1)

=

3x
x2-1

(2)原式=

(x+1)(x-1)
(x-1)2
+
x(x-2)
x-2
1
x

=

x+1
x-1
+1

=

2x
x-1

当x=2时,原式=

2x
x-1
=4.

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