问题
解答题
计算：
|
答案
原式=
÷m(1-m) (m+1)(m-1)
•m m-1 (m+1)2 (m-1)2
=
•-m(m-1) (m+1)(m-1)
•m-1 m (m+1)2 (m-1)2
=-
．m+1 m-1
搜题请搜索小程序“爱下问搜题”
计算：
|
原式=
÷m(1-m) (m+1)(m-1)
•m m-1 (m+1)2 (m-1)2
=
•-m(m-1) (m+1)(m-1)
•m-1 m (m+1)2 (m-1)2
=-
．m+1 m-1
