问题 填空题

若2(4a-2)-6=3(4a-2),则代数式a2-3a+4=______.

答案

2(4a-2)-6=3(4a-2),

去括号得:8a-4-6=12a-6,

移项得:8a-12a=4,

解得:a=-1,

∴a2-3a+4=(-1)2+3+4=8.

故本题答案为:8.

改错题

短文改错(共10小题,每小题1分,满分10分)

此题要求改正所给短文中的错误。对标有题号的每一行作出判断:每行只有一个错误,请按下列情况改正:

该行多一个词:把多余的词用斜线(\)划掉,在该行右边横线上写出该词,并也用斜线划掉。

该行缺一个词:在缺词处加一个漏字符号(^),在该行右边横线上写出该加的词。

该行错一个词:在错的词下划一横线,在该行右边横线上写出改正后的词。

注意:请在答题卡上作答。

It was 7:15 in the morning of February 8, 2007.I was               小题1:          

walking along Park Road towards the east while an                            小题2:          

old man came out of the park on the other sides of the                        小题3:          

street.Then I saw a yellow car to drive up and make a right               小题4:          

turn into Park Road.The car hit the man while she                           小题5:          

was crossing the road.He falls with a cry.The car drove off            小题6:          

at full speed heading west.I noticed driver was a woman                   小题7:          

wore a pair of glasses and the plate number was AC864.                     小题8:          

Two minutes late, I managed to stop a passing car, took the                 小题9:          

old man to the nearest hospital but paid for his treatment.                   小题10:                                 

单项选择题 B1型题