问题
解答题
已知x=
|
答案
(1)证明:∵x=
,y=
-3 2
+2 7
=1 2+
+14
+6 21 1 (
+2
)(7
+3
)2
∴x-y=
-
-3 2
+2 7 1 (
+2
)(7
+3
)2
=1-1 (
+2
)(7
+3
)2
=0;
(2)x3y-xy3=xy(x+y)(x-y)
∵由(1)得x-y=0
∴原式=0.
已知x=
|
(1)证明:∵x=
,y=
-3 2
+2 7
=1 2+
+14
+6 21 1 (
+2
)(7
+3
)2
∴x-y=
-
-3 2
+2 7 1 (
+2
)(7
+3
)2
=1-1 (
+2
)(7
+3
)2
=0;
(2)x3y-xy3=xy(x+y)(x-y)
∵由(1)得x-y=0
∴原式=0.