问题 解答题
当x=3,y=-2时,求下列代数式的值.
①x2-y2
x+y
x-y

③x2-2xy+y2
3x2-
5
2
y

1
x
+
1
y

⑥4x2-3xy+5y2
答案

当x=3,y=-2时,

①x2-y2

=9-4

=5;

x+y
x-y

=

3-2
3+2

=

1
5

③x2-2xy+y2

=9+12+4

=25;

④3x2-

5
2
y

=27+5

=32;

1
x
+
1
y

=

1
3
-
1
2

=-

1
6

⑥4x2-3xy+5y2

=36+18+20

=74.

单项选择题 A1型题
单项选择题