问题
计算题
计算:[x(x2y2-xy)-y(x2-x3y)]÷3x2y
答案
解:原式=(x3y2-x2y-x2y+x3y2)÷3x2y
=(2x3y2-2x2y)÷3x2y
=xy
计算:[x(x2y2-xy)-y(x2-x3y)]÷3x2y
解:原式=(x3y2-x2y-x2y+x3y2)÷3x2y
=(2x3y2-2x2y)÷3x2y
=xy