问题
计算题
计算:
(1) (x+3)( 3-2x) (2)[x(x2y2+xy)- y(x2-x3y)]÷3x2y
答案
解:(1)原式=3x-2x2+9-6x =-2x2-3x+9
(2)原式=(x3y2+x2y-x2y+x3y2)÷3x2y =2x3y2÷3x2y=xy
计算:
(1) (x+3)( 3-2x) (2)[x(x2y2+xy)- y(x2-x3y)]÷3x2y
解:(1)原式=3x-2x2+9-6x =-2x2-3x+9
(2)原式=(x3y2+x2y-x2y+x3y2)÷3x2y =2x3y2÷3x2y=xy