问题
计算题
计算: (1)x(y﹣1)﹣y(x﹣1);
(2)(x﹣3y)(x+3y)﹣(x﹣3y)2.
答案
解:(1)原式=(xy﹣x)﹣(xy﹣y)=xy﹣x﹣xy+y=y﹣x,
(2)原式=(x﹣3y)(x+3y﹣x+3y)=(x﹣3y)6y=6xy﹣18y2.
计算: (1)x(y﹣1)﹣y(x﹣1);
(2)(x﹣3y)(x+3y)﹣(x﹣3y)2.
解:(1)原式=(xy﹣x)﹣(xy﹣y)=xy﹣x﹣xy+y=y﹣x,
(2)原式=(x﹣3y)(x+3y﹣x+3y)=(x﹣3y)6y=6xy﹣18y2.