问题 解答题
计算:
(1)(-a2)-(-2a32
(2)(-3x)(2x3-3x2+4x-1)
(3)(2x-3)(3x2+2x-5)
(4)(-x)8÷(-x)5
(5)-24x5y5z÷32x2y3
(6)27a2bc-(-
1
3
bc23÷
1
5
a2b3c6
(7)[-4x(2xy+3xy2)+12(x2y)2y3]÷(-6xy)
(8)[-2-3-8-1×(-1)-2]×(-
1
2
-2×70
答案

(1)原式=(-a2)•4a6=-4a10

(2)原式=-6x4+9x3-12x2+3x;

(3)原式=6x3-5x2-11x+15;

(4)原式=-x3

(5)原式=-

3
4
x3y2z

(6)原式=-9a2b2c3÷

1
5
a2b3c6=-45bc;

(7)原式=[-8x2y-12x2y2+12x4y5]÷(-6xy)=

4
3
x+2xy-2x3y4

(8)原式=[-

1
8
-
1
8
×1]×4×1=-
1
4
×4=-1.

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