问题
解答题
先化简,再求值:[(x+2y)(x-2y)-(x+4y)2]÷4y,其中x=-5,y=2.
答案
[(x+2y)(x-2y)-(x+4y)2]÷4y,
=[x2-4y2-(x2+8xy+16y2)]÷4y,
=(x2-4y2-x2-8xy-16y2)÷4y,
=(-20y2-8xy)÷4y,
=-5y-2x,
当x=-5,y=2时,原式=-5×2-2×(-5)=-10+10=0.
先化简,再求值:[(x+2y)(x-2y)-(x+4y)2]÷4y,其中x=-5,y=2.
[(x+2y)(x-2y)-(x+4y)2]÷4y,
=[x2-4y2-(x2+8xy+16y2)]÷4y,
=(x2-4y2-x2-8xy-16y2)÷4y,
=(-20y2-8xy)÷4y,
=-5y-2x,
当x=-5,y=2时,原式=-5×2-2×(-5)=-10+10=0.