设S=1+3(x-1)+3(x-1)2+(x-1)3,S=( )
A.(x-1)3
B.(x-2)3
C.(x+1)3
D.x3
S=1+3(x-1)+3(x-1)2+(x-1)3=
•13+C 03
•12•(x-1)+C 13
•1•(x-1)2+C 23
•(x-1)3=[1+(x-1)]3=x3C 33
故选D.
设S=1+3(x-1)+3(x-1)2+(x-1)3,S=( )
A.(x-1)3
B.(x-2)3
C.(x+1)3
D.x3
S=1+3(x-1)+3(x-1)2+(x-1)3=
•13+C 03
•12•(x-1)+C 13
•1•(x-1)2+C 23
•(x-1)3=[1+(x-1)]3=x3C 33
故选D.